Theorie der Geldpolitik 1 S. 59
[COLOR=Black]Hallo!
Kann mir jemand weiterhelfen bei der Aufgabe aus dem Skirp (Theorie der Geldpolitik) Seite 59, ich habe folgende Berechnung und weiter komme ich nicht:
L= E ( 0,5 ((Pi -Pi*)[/COLOR][COLOR=Black]^2+ b(y-y*)[/COLOR][COLOR=Black]^2 ))
L= E ( 0,5 ((Pi -Pi*)[/COLOR][COLOR=Black]^2+ b(cPi -CPi+ Epsilon-y*)[/COLOR][COLOR=Black]^2 ))
L= E ( 0,5 ((Pi -Pi*)[/COLOR][COLOR=Black]^2+ b(cPi -CPi+ Epsilon-y*)[/COLOR][COLOR=Black]^2 ))
dL/ dP = E ( 0,5 (2(Pi -Pi*)[/COLOR][COLOR=Black]+ 2cb(cPi -CPi[/COLOR][COLOR=Black]^e[/COLOR][COLOR=Black]+ Epsilon-y*)[/COLOR][COLOR=Black])
0= Pi -Pi*[/COLOR][COLOR=Black]+ cb(cPi -CPi[/COLOR][COLOR=Black]^[/COLOR][COLOR=Black]e+ Epsilon-y*)
0= Pi -Pi*[/COLOR][COLOR=Black]+ c[/COLOR][COLOR=Black]^2[/COLOR][COLOR=Black]bPi -C[/COLOR][COLOR=Black]^2[/COLOR][COLOR=Black]Pi[/COLOR][COLOR=Black]^e[/COLOR][COLOR=Black]+cb Epsilon-cby*
Pi [/COLOR][COLOR=Black]+ c[/COLOR][COLOR=Black]^2[/COLOR][COLOR=Black]bPi=Pi*[/COLOR][COLOR=Black]+[/COLOR][COLOR=Black]C[/COLOR][COLOR=Black]^2b[/COLOR][COLOR=Black]Pi[/COLOR][COLOR=Black]^e[/COLOR][COLOR=Black]-cb Epsilon+cby*
Pi [/COLOR][COLOR=Black]+ (1+c[/COLOR][COLOR=Black]^2[/COLOR][COLOR=Black]b)=Pi*[/COLOR][COLOR=Black]+[/COLOR][COLOR=Black]C[/COLOR][COLOR=Black]^2b[/COLOR][COLOR=Black]Pi[/COLOR][COLOR=Black]^e[/COLOR][COLOR=Black]-cb Epsilon+cby*
E(Pi) [/COLOR][COLOR=Black]+ (1+c[/COLOR][COLOR=Black]^2[/COLOR][COLOR=Black]b)=E(Pi*)[/COLOR][COLOR=Black]+[/COLOR][COLOR=Black]C[/COLOR][COLOR=Black]^2b E([/COLOR][COLOR=Black]Pi[/COLOR][COLOR=Black]^e)[/COLOR][COLOR=Black]-cb E(Epsilon)+cb E (y*)
Pi[/COLOR][COLOR=Black]^e[/COLOR][COLOR=Black]+ (1+c[/COLOR][COLOR=Black]^2[/COLOR][COLOR=Black]b)=Pi[/COLOR][COLOR=Black]^e[/COLOR][COLOR=Black]+[/COLOR][COLOR=Black]C[/COLOR][COLOR=Black]^2b[/COLOR][COLOR=Black]Pi[/COLOR][COLOR=Black]^e[/COLOR][COLOR=Black]-0+cby*
Pi[/COLOR][COLOR=Black]^e[/COLOR][COLOR=Black]+c[/COLOR][COLOR=Black]^2[/COLOR][COLOR=Black]bPi[/COLOR][COLOR=Black]^e=Pi[/COLOR][COLOR=Black]^e[/COLOR][COLOR=Black]+[/COLOR][COLOR=Black]C[/COLOR][COLOR=Black]^2b[/COLOR][COLOR=Black]Pi[/COLOR][COLOR=Black]^e[/COLOR][COLOR=Black]-0+cby*
und wenn ich jetzt auf den anderen Siete multipliziere: -Pi[/COLOR][COLOR=Black]^e-[/COLOR][COLOR=Black]C[/COLOR][COLOR=Black]^2b[/COLOR][COLOR=Black]Pi[/COLOR][COLOR=Black]^e
[/COLOR][COLOR=Black]
dann habe ich : 0= cby*
ich suche aber Pi[/COLOR][COLOR=Black]^e
[/COLOR]
Comments
Tinkerbell
Contributions on this page: 1
View profileL= E ( 0,5 ((Pi -Pi*)^2+ b(y-y*)^2 ))
L= E ( 0,5 ((Pi -Pi*)^2+ b(cPi –Cpi[COLOR=red]^e[/COLOR]+ Epsilon-y*)^2 ))
L= E ( 0,5 ((Pi -Pi*)^2+ b(cPi –Cpi[COLOR=red]^e[/COLOR]+ Epsilon-y*)^2 ))
dL/ dP[COLOR=red]i[/COLOR] = E ( 0,5 (2(Pi -Pi*)+ 2cb(cPi -CPi^e+ Epsilon-y*))
0= Pi -Pi*+ cb(cPi -cPi^e+ Epsilon-y*)
0= Pi -Pi*+ c^2bPi -C^2[COLOR=red]b[/COLOR]Pi^e+cb Epsilon-cby*
Pi [COLOR=red]* [/COLOR]c^2bPi=Pi*+C^2bPi^e-cb Epsilon+cby*
Pi [COLOR=red]*[/COLOR] (1+c^2b)=Pi*+C^2bPi^e-cb Epsilon+cby*
E(Pi)[COLOR=red] *[/COLOR][/COLOR] (1+c^2b)=E(Pi*)+C^2b E(Pi^e)-cb E(Epsilon)+cb E (y*)
Pi^e* (1+c^2b)= 0+C^2bPi^e-0+cby*
Pi^e+c^2bPi^e=[COLOR=red]0[/COLOR]+C^2bPi^e-0+cby*
[COLOR=red]-> [/COLOR][/COLOR][COLOR=red]piê + 2b²piê –2b²piê = bcy*[/COLOR][/COLOR]
[COLOR=red]piê=bcy*[/COLOR][/COLOR]
[/COLOR]
[COLOR=#ff0000]Dein Erwartungswert über pi* war einfach nur falsch?[/COLOR][/COLOR]
tatias
Contributions on this page: 2
View profileVielen Dank!
Hatte den gleichen Fehler in der Einsendearbeit!